the resultant of 2 forces p &q acting at certain angles is x and that of p are acting at same angle is also x .the resultant of q& r again acting at same angle is y.prove that (a) (p=x^2+qr)^.5=qr(q+r)/q^2+r^2-y^2 (b) p+q+r=0,then x=y; the resultant of 2 forces p &q acting at certain angles is x and that of p are acting at same angle is also x .the resultant of q& r again acting at same angle is y.prove that (a) (p=x^2+qr)^.5=qr(q+r)/q^2+r^2-y^2 (b) p+q+r=0,then x=y
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